... system.1
For the partial derivative with respect to \bgroup\color{blue}$ X_i$\egroup in Equation 20-3, there is a constraint between the variables \bgroup\color{blue}$ \sum X_i = 1$\egroup, that must be considered when taking the derivative of the molar free energy. Later, we will derive an important graphical construction for the determination of \bgroup\color{blue}$ \mu_i$\egroup from curves of \bgroup\color{blue}$ \ensuremath{\overline{G}}$\egroup.
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... mixture2
That is a system of particles that occupy a neglible volume and are non-interacting. Each particle is identified with a chemical species. If the species are assumed to react, then the combinations of particles to form another vary according to the stoicheometric coefficients of a chemical reaction of the form \bgroup\color{blue}$ rR + qQ \ensuremath{\rightleftharpoons}bB + aA$\egroup
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...#tex2html_wrap_inline3301#3
All the chemical species \bgroup\color{blue}$ i$\egroup should use the same reference pressure so the subscript can be dropped. Whenever a subscript appears below, it will refer to a partial pressure, i.e., \bgroup\color{blue}$ \sum_i P_i = \ensuremath{{P}^{\mbox{total}}}$\egroup
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... gas.4
An ideal single gas: \bgroup\color{blue}$ \mu(P,T)= \ensuremath{{\mu}_\circ}(T)
+ RT \log P/\ensuremath{{P}_\circ}$\egroup. Note, you will often see formulae like \bgroup\color{blue}$ \mu =
\ensuremath{{\mu}_\circ} + RT \log P$\egroup, you know that \bgroup\color{blue}$ P$\egroup cannot have units-so a convenient \bgroup\color{blue}$ \ensuremath{{P}_\circ} = 1$\egroup has been picked.
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