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Single Component Phase Equilibria

When there is only one degree of freedom in a single component phase diagram, it was shown above that there must be a relation between \bgroup\color{blue}$ dP$\egroup and \bgroup\color{blue}$ dT$\egroup for the system to remain in two phase equilibrium. Such a relation can be derived as follows:

$\displaystyle \input{equations/clausius-clapeyron}$ (26-2)

Equation 26-2 is the famous Clausius-Clapeyron equation.


Consider the behavior of the molar free energy (or \bgroup\color{blue}$ \mu$\egroup) on slices of Figure 26-1 at constant \bgroup\color{blue}$ P$\egroup and \bgroup\color{blue}$ T$\egroup:

Figure 26-2: Considerations of the molar Gibbs free energy on slices of the single component phase diagram along lines of constant $ T$ and constant $ P$.
\begin{figure}\resizebox{6in}{!}
{\epsfig{file=figures/20-1A.eps}}
\end{figure}

Figure: Behavior of $ \ensuremath{\overline{G}} = \mu$ at constant $ P$ as a function of $ T$. Where the curvature of $ \ensuremath{\overline{G}}$ changes sign, the system is unstable. The liquid and vapor curves must be connected to each other and this is illustrated with the "spiny-looking" curve with opposite curvature. The curve for solid is not connected to the others.
\begin{figure}\resizebox{6in}{!}
{\epsfig{file=figures/20-1B.eps}}
\end{figure}


Figure: Behavior of $ \ensuremath{\overline{G}} = \mu$ at constant $ T$ as a function of $ P$.
\begin{figure}\resizebox{6in}{!}
{\epsfig{file=figures/20-1C.eps}}
\end{figure}


Figure 26-5: Example of single component phase diagram plotted with one derived intensive variable.
\begin{figure}\resizebox{6in}{!}
{\epsfig{file=figures/pt-vs-vt.eps}}
\end{figure}

What would the plot look like with two extensive variables plotted?


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W. Craig Carter 2002-11-21