Recall that
is not a perfect
differential.
Let's consider
for an ideal gas
undergoing a reversible process.
![]() |
(11-17) |
for an ideal gas
![]() |
(11-18) |
![]() |
(11-19) |
Now divide through by
![]() |
(11-20) |
Notice that we have separated the equation
into something that is integrable over
segments of
and
and thus over any
curve.
Therefore,
is a ``perfect
differential'' and it must then be
a state function for an ideal gas.