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The Change of Temperature with the Addition of Heat

Question: What is the temperature of solid water (ice)?

a
$ \approx 0^\circ$ C
b
$ \approx 273$K
c
Any of the above (a and/or b)
d
$ \approx 10^\circ$ C
e
$ \approx -10^\circ$
f
any of the above (d and/or e and/or c)

Consider a mole of ice at \bgroup\color{blue}$ -100^\circ$\egroupC that has heat added to it at a constant rate ( \bgroup\color{blue}$ \dot{q} =$\egroup constant) and a constant pressure. (Slow enough so that the body has a uniform temperature; i.e., reversibly at constant atmospheric pressure). What will be the temperature as a function of time?

Figure 14-1: Heating up cold ice at a constant rate.
\begin{figure}\resizebox{6in}{!}
{\epsfig{file=figures/heat-h20.eps}}
\end{figure}

What is the slope of the initial part of the curve (Region I)?


$\displaystyle \input{equations/92A}$ (14-1)


Therefore the slope is \bgroup\color{blue}$ \frac{1}{C_P}$\egroup:

Region I

Slope = $ \frac{1}{C_{P(\mbox{(solid)}}}$

Region III

Slope = $ \frac{1}{C_{P(\mbox{(liquid)}}}$

Question: What is happening in Region II?


Question: What is the heat absorbed in Region II? Where does it go?

$\displaystyle \input{equations/92B}$ (14-2)

This is equivalent to the heat absorbed by the system at constant temperature--we identified this quantity with the state function enthalpy, \bgroup\color{blue}$ H= U + PV$\egroup. The change in the constant pressure heat state function \bgroup\color{blue}$ \Delta H$\egroup, is the heat absorbed during the transformation.



next up previous
Next: Heat of Transformation Up: Lecture_14_web Previous: Lecture_14_web
W. Craig Carter 2002-10-05